What distance does the Wagon travel in this time?

Posted on November 19, 2009 by admin

A poorly tuned Wagon R can accelerate from rest to a speed of 28 m/s in 20s.
What distance does the wagon travel in this time?
How do I figure it out.

Acceleration of the wagon
= a
= (v-u).t
where v is the final speed of the wagon = 28m/s
u is the initial speed of the wagon = 0m/s
t is the time taken to accelerate from rest to 28m/s = 20s
= (28-0)/20
= 1.4

Distance that the wagon travels in this time
= S
= ut+0.5at^2
where u is the initial speed of the wagon=0m/s
t is the time taken to accelerate = 20s
a is the acceleration of the wagon = 1.4ms^(-2)
= 0*20+0.5*(1.4)*(20)^2
= 280

So, the wagon travels a distance of 280m in this time.

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2 Responses to What distance does the Wagon travel in this time?

  1. gabriel BB says:
    November 19, 2009 at 3:30 pm

    Acceleration of the wagon
    = a
    = (v-u).t
    where v is the final speed of the wagon = 28m/s
    u is the initial speed of the wagon = 0m/s
    t is the time taken to accelerate from rest to 28m/s = 20s
    = (28-0)/20
    = 1.4

    Distance that the wagon travels in this time
    = S
    = ut+0.5at^2
    where u is the initial speed of the wagon=0m/s
    t is the time taken to accelerate = 20s
    a is the acceleration of the wagon = 1.4ms^(-2)
    = 0*20+0.5*(1.4)*(20)^2
    = 280

    So, the wagon travels a distance of 280m in this time.
    References :

  2. nozar nazari says:
    November 19, 2009 at 4:01 pm

    V final=at +V0
    28=20t, a=28/20=1.4 m/sec^2
    D=1/2(a)t^2 +0=1/2(1.4)20^2=280 meters.
    God bless you.
    References :